Quote:
Originally Posted by pseudonous  Romansh
I agree largely with what you are saying but I would add that in some situations we do have a way of telling that 1/O(AB) gives us better odds than 1/O(ABC). This is what I was trying to illustrate in my previous post perhaps I need to rethink this. Did you have any specific objection to my previous post or was it just in general unclear? I am thinking it may be that I am not using O(AB) in quite the same way as you. | Nous,
I'm not sure ... a little out of my depth here
But it would seem to me we should be able to say
1/O (AB) > 1/O (ABC)
Because O (ABCDEF..........) should approach 1?
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